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An experiment was carried out to investigate the effect ofspecies (factor A, with I = 4) and grade (factor B, with J = 3) onbreaking strength of wood specimens. One observation was made foreach species—grade combination—resulting in SSA = 444.0, SSB =424.6, and SSE = 122.4. Assume that an additive model isappropriate. (a) Test H0: α1 = α2 = α3 = α4 = 0 (no differences intrue average strength due to species) versus Ha: at least one αi ≠0 using a level 0.05 test. Calculate the test statistic. (Roundyour answer to two decimal places.) f = 1 What can be said aboutthe P-value for the test? P-value > 0.100 0.050 < P-value< 0.100 0.010 < P-value < 0.050 0.001 < P-value <0.010 P-value < 0.001 State the conclusion in the problemcontext. Reject H0. The data suggests that true average strength ofat least one of the species is different from the others. Fail toreject H0. The data does not suggest any difference in the trueaverage strength due to species. Reject H0. The data does notsuggest any difference in the true average strength due to species.Fail to reject H0. The data suggests that true average strength ofat least one of the species is different from the others. (b) TestH0: β1 = β2 = β3 = 0 (no differences in true average strength dueto grade) versus Ha: at least one βj ≠ 0 using a level 0.05 test.Calculate the test statistic. (Round your answer to two decimalplaces.) f = 4 What can be said about the P-value for the test?P-value > 0.100 0.050 < P-value < 0.100 0.010 < P-value< 0.050 0.001 < P-value < 0.010 P-value < 0.001 Statethe conclusion in the problem context. Reject H0. The data does notsuggest any difference in the true average strength due to grade.Fail to reject H0. The data does not suggest any difference in thetrue average strength due to grade. Reject H0. The data suggeststhat true average strength of at least one of the grades isdifferent from the others. Fail to reject H0. The data suggeststhat true average strength of at least one of the grades isdifferent from the others.