An element crystallizes in a body-centered cubic lattice. The edge of the unit cell is 3.28...

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Chemistry

An element crystallizes in a body-centered cubic lattice. Theedge of the unit cell is 3.28 Ã… in length, and the density of thecrystal is 6.50 g/cm3 .
a.) Calculate the atomic weightof the element.

Answer & Explanation Solved by verified expert

4.2 Ratings (663 Votes)

Since, edge of the unit cell is 3.28 Ã…

volume of the unit cell = 3 x 3.28 x 10^-8 cm³

= 9.84 x 10^-8 cm³

Given that density of cell = 6.50 = weight of the cell/ volume of the cell

Hence, weight of the cell = 6.5 x (9.84 x 10^-8)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 63.96 x 10^-8g

But in body cantered cubic lattice contain two atoms each

Hence atomic weight = weight of the unit cell / 2

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 31.98 x 10^-8 g

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An element crystallizes in a body-centered cubic lattice. The edge of the unit cell is 3.28...

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70.2K

Verified Solution

Question

Chemistry

An element crystallizes in a body-centered cubic lattice. Theedge of the unit cell is 3.28 Ã… in length, and the density of thecrystal is 6.50 g/cm3 .
a.) Calculate the atomic weightof the element.

Answer & Explanation Solved by verified expert

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An element crystallizes in a body-centered cubic lattice. The edge of the unit cell is 3.28...

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70.2K

Verified Solution

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Chemistry

An element crystallizes in a body-centered cubic lattice. Theedge of the unit cell is 3.28 Ã… in length, and the density of thecrystal is 6.50 g/cm3 .a.) Calculate the atomic weightof the element.

Answer & Explanation Solved by verified expert

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An element crystallizes in a body-centered cubic lattice. Theedge of the unit cell is 3.28 Ã… in length, and the density of thecrystal is 6.50 g/cm3 .
a.) Calculate the atomic weightof the element.