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An electron is released from rest at the negative plate of a parallel plate capacitor and...

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Physics

An electron is released from rest at the negative plate of aparallel plate capacitor and accelerates to the positive plate (seethe drawing). The plates are separated by a distance of 1.4 cm, andthe electric field within the capacitor has a magnitude of 2.0 x10^6 V/m. What is the kinetic energy of the electron just as itreaches the positive plate?

Answer & Explanation Solved by verified expert
4.5 Ratings (739 Votes)

Total force acting on electron= qE

                                                =1.6*10-19*2.0*106

                                                =3.2*10-13 N

Change in KE=work done by field=force*displacement

                =3.2*10-13*0.014

                =4.48*10-15 J

Thus final KE of electron=4.48*10-15 J or 27.96*103 eV
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