An electrochemical cell is based on the following two
half-reactions:
Ox: Pb(s)→Pb2+(aq, 0.15 M )+2e−
Red:MnO−4(aq, 1.70 M...
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Chemistry
An electrochemical cell is based on the following twohalf-reactions: Ox: Pb(s)→Pb2+(aq, 0.15 M )+2e− Red:MnO−4(aq, 1.70 M )+4H+(aq,1.5 M )+3e−→ MnO2(s)+2H2O(l)
Compute the cell potential at 25 ∘C.
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4.2 Ratings (567 Votes)
Given that Red MnO4aq 170 M 4Haq 15 M 3 e MnO2s2H2Ol 170 1 Ox Pbs Pb2aq 015 M 2e 0126 2 Multiply 1 with 2 and 2 with 3 2MnO4aq
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