An astronaut shipwrecked on a distant planet is on top of a sheer vertical cliff (letâ€™s...

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Physics

An astronaut shipwrecked on a distant planet is on top of asheer vertical cliff (letâ€™s call it point P), which he wishessomehow to climb down. He does not know the acceleration due togravity on the planet, and he has only a good watch with which tomake measurements. He wants to learn the height of the cliff (fromP down to the bottom). To do this,he makes two measurements. 1) Hedrops a rock fall from rest off the cliff edge (from point P) andfinds that the rock takes 4.15 s to reach the bottom. 2) He tossesanother rock straight upward from P such that it rises a height ofwhat he estimates to be 2 m (up from P) before it falls to theground below. This time the rock takes 6.30 s from the originaltoss to hit the bottom. What is the height of the cliff (point Pdown to the bottom below)?

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3.7 Ratings (572 Votes)

We have the equation of motionWhere S is displacementu is initial velocitya is accelerationt is time of motionMotion of the rock when astronaut directly See Answer

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