Solution:
We know ∆Tf = -Kf x m
Where, ∆Tf = depression of freezing point,
Kf = is the freezing point depression constant, and
m = molality.
Concentration of the protein = 10g dm-3
                                              Â
=10/17000 mol dm-3 = 5.88x10-4 mol/L
                                                                                  Â
= 5.88x10-4 mol/kg    Â
(assuming density of water = 1kg/L)
Therefore, ∆Tf = -Kf x m =
-274.86x5.88x10-4 = -0.16 K
        (since,
kf = 274.86 K/m)
Similarly, Concentration of lysozyme = 10g dm-3
                                              Â
=10/14500 mol dm-3 = 6.89x10-4 mol/L
                                                                                  Â
= 6.89x10-4 mol/kg    Â
(assuming density of water = 1kg/L)
Therefore, ∆Tf = -Kf x m =
-274.86x6.89x10-4 = -0.19
KÂ Â Â Â Â Â Â Â Â (since,
kf = 274.86 K/m)
