An alpha particle with kinetic energy 10.5 MeV makes a collision with lead nucleus, but it...

80.2K

Verified Solution

Question

Physics

An alpha particle with kinetic energy 10.5 MeV makes a collisionwith lead nucleus, but it is not \"aimed\" at the center of the leadnucleus, and has an initial nonzero angular momentum (with respectto the stationary lead nucleus) of magnitude L=p0b, where p0 is themagnitude of the initial momentum of the alpha particle andb=1.20×10−12 m . (Assume that the lead nucleus remains stationaryand that it may be treated as a point charge. The atomic number oflead is 82. The alpha particle is a helium nucleus, with atomicnumber 2.)

What is the distance of closest approach?

Repeat for b=1.40×10−13 mm .

Repeat for b=1.20×10−14 mm .

Answer & Explanation Solved by verified expert
3.8 Ratings (487 Votes)
The    See Answer
Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:
  • Unlimited Question Access with detailed Answers
  • Zin AI - 3 Million Words
  • 10 Dall-E 3 Images
  • 20 Plot Generations
  • Conversation with Dialogue Memory
  • No Ads, Ever!
  • Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!
Become a Member

Other questions asked by students