Ammonia reacts with diatomic oxygen to form nitric oxide and water vapor: 40.0 g NH3 and...

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Ammonia reacts with diatomic oxygen to form nitric oxide andwater vapor: 40.0 g NH₃ and 50.0 g O₂ areallowed to react according to the following equation:
4NH₃ + 5O₂ Ã 4NO + 6H₂O
4. What is the maximum number of grams of nitric oxide that canbe produced in this experiment?
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â a. 50.0 g
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â b. 70.6gÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â c. 37.5 g
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â d. 40.0 g
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â e. 58.6 g

Answer & Explanation Solved by verified expert

4.1 Ratings (626 Votes)

Solution Balanced reaction equation 4NH3 5O2 4NO6H2O 400 gNH3 and 500 g O2 Maximum mass of NO produced Lets first calculate moles of the NH3 and O2 Moles mass molar mass Moles See Answer

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Ammonia reacts with diatomic oxygen to form nitric oxide and water vapor: 40.0 g NH3 and...

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