aluminum sulfide and water react to form aluminum hydroxide and hydrogen sulfide gas. suppose 128.00 g...

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Chemistry

aluminum sulfide and water react to form aluminum hydroxide andhydrogen sulfide gas. suppose 128.00 g of aluminum are added to154.45 mL of water(d=1.00 g/ml). Answer the followingquestions.

a).before the reaction, how many water molecules are present inthe reaction mixture?

b) when the reaction is finished. what mass, in g, of aluminumhydroxide can theoretically be produced?

c) limiting reactant?

d) mass in grams of remaining excessreactant if the theoreticalyield of aluminum hydroxide is obtained?

e)if the percent yield is 87.6% under these conditions what isthe actual yiel of product aluminum hydroxide?

please show how you solve

Answer & Explanation Solved by verified expert
3.9 Ratings (577 Votes)
Al2S3 6H2O 2AlOH3 3H2S is balanced equation a H2O mass volume x density 15445 x 1 15445 g H2O moles mass of H2O molarmass of H2O 154451801528 857328 Number of H2O molecules moles    See Answer
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