60.1K

Verified Solution

Link Copied!

Allen's hummingbird (Selasphorus sasin) has beenstudied by zoologist Bill Alther.† Suppose a small group of 18Allen's hummingbirds has been under study in Arizona. The averageweight for these birds is x = 3.15 grams. Based onprevious studies, we can assume that the weights of Allen'shummingbirds have a normal distribution, with ? = 0.30gram.

(a) Find an 80% confidence interval for the average weights ofAllen's hummingbirds in the study region. What is the margin oferror? (Round your answers to two decimal places.)

lower limit
upper limit
margin of error

(b) What conditions are necessary for your calculations? (Selectall that apply.)

uniform distribution of weights? is unknown?is knownn is largenormal distribution of weights

(c) Interpret your results in the context of this problem.

The probability that this interval contains the true averageweight of Allen's hummingbirds is 0.20.The probability to the trueaverage weight of Allen's hummingbirds is equal to the samplemean.    There is a 20% chance that theinterval is one of the intervals containing the true average weightof Allen's hummingbirds in this region.There is an 80% chance thatthe interval is one of the intervals containing the true averageweight of Allen's hummingbirds in this region.The probability thatthis interval contains the true average weight of Allen'shummingbirds is 0.80.

(d) Find the sample size necessary for an 80% confidence level witha maximal margin of error E = 0.12 for the mean weights ofthe hummingbirds. (Round up to the nearest whole number.)
hummingbirds