According to actuarial tables, life spans in the United States are approximately normally distributed with a...

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According to actuarial tables, life spans in the United Statesare approximately normally distributed with a mean of about 75years and a standard deviation of about 16 years.
1) Find the probability that a randomly selected person livesbetween 60 less than 90 years.
2) Find the probability that a randomly selected person livesless than 50 years or more than 100 years.
3) Find the probability that a randomly selected person livesexactly 75 years.
4) What age is considered to be the 99th percentile?
5) What age is considered to be in the 10th percentile?

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SolutionGivenlife spans in the United States are approximatelynormally distributed with a mean of about 75 years and a standarddeviation of about 16 yearsThus andPart 1 Find the probability that a randomlyselected person lives between 60 less than 90 yearsP 60 X 90 Find z scoresThus we getP 60 X 90 P 094 Z 094P 60 X 90 P Z 094 PZ 094 Look in z table for z 09 and 004 as well as for z See Answer

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