According to a survey in a​ country, 18​% of adults do not own acredit card. Suppose a simple random sample of 900 adults isobtained. ​(b) What is the probability that in a random sample of900 ​adults, more than 22​% do not own a credit​ card? Theprobability is what.? ​(Round to four decimal places as​ needed.)Interpret this probability. If 100 different random samples of 900adults were​ obtained, one would expect nothing to result in morethan 22​% not owning a credit card. ​(Round to the nearest integeras​ needed.).  

(c) What is the probability that in a random sample of 900​adults, between 17​% and 22​% do not own a credit​ card?

Interpret this probability. If 100 different random samples of900 adults were​ obtained, one would expect ? to result in between17​% and 22​% not owning a credit card.

​(Round to the nearest integer as​ needed.)

Would it be unusual for a random sample of 900 adults to resultin 153 or fewer who do not own a credit​ card? Why? Select thecorrect choice below and fill in the answer box to complete yourchoice

The result

is notis not

unusual because the probability that

ModifyingAbove p with caretp

is less than or equal to the sample proportion is

nothing​,

which is

greatergreater

than​ 5%.

B.The result

is notis not

unusual because the probability that

ModifyingAbove p with caretp

is less than or equal to the sample proportion is

nothing​,

which is

lessless

than​ 5%.

C.The result

isis

unusual because the probability that

ModifyingAbove p with caretp

is less than or equal to the sample proportion is

nothing​,

which is

lessless

than​ 5%.

D.The result

isis

unusual because the probability that

ModifyingAbove p with caretp

is less than or equal to the sample proportion is

nothing​,

which is

greatergreater

than​ 5%.