According to a poll of adults about 41% work during their summer vacation. Suppose that this...

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According to a poll of adults about 41% work during their summervacation. Suppose that this claim about the population proportionis true. Now if we take a sample of 75 adults, and find the sampleproportion [^(p)] of adults who work during summervacation.

What is the expected value of sample proportion[^(p)]?

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What is the standard deviation of sample proportion[^(p)]?

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The shape of the sampling distribution of sample proportion[^(p)] will be roughly like a
normal distribution
uniform distribution
Poisson distribution
student's t distribution
binomial distribution

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P(0.30 ≤ [^(p)] ≤ 0.47) =

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Is the sample large enough to compute the aboveprobability?
Yes, because np ≥ 10 and n(1−p) ≥10.
No, the sample size is not sufficiently large. We actually had toassume normally distributed population.
Yes, because n ≥ 30
Yes, because np ≥ 10.
Yes, because the number of successes and failures are both largerthan 10.

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Find c such that P([^(p)] ≥c) = 0.7

Answer & Explanation Solved by verified expert
3.7 Ratings (422 Votes)
Since the sample size is greater than 30    See Answer
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