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A watermelon seed has the following coordinates: x = -6.4 m, y = 5.0 m, and...

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Physics

A watermelon seed has the following coordinates: x =-6.4 m, y = 5.0 m, and z = 0 m. Find its positionvector as (a) a magnitude and (b)an angle relative to the positive direction of the x axis.If the seed is moved to the xyz coordinates (3.0 m, 0 m, 0m), what is its displacement as (c) a magnitudeand (d) an angle relative to the positivedirection of the x axis? Put the angles in the range(-180°, 180°].

Answer & Explanation Solved by verified expert
4.3 Ratings (641 Votes)
Part 1 When seed is at coordinate x 64 m y 50 m z 0 m So r position vector about origin 64 i 50 j 0 k Magnitude of position vector will be r sqrt642    See Answer
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