A voltage source, Vs = 180sin760t is in series with an inductor L = 435 mH,...

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A voltage source, Vs = 180sin760t is in series with an inductorL = 435 mH, a capacitor C = 2 μF, and a resistor R = 240 Ω.

c) What is the phase angle of this circuit? Does the currentlead the total voltage or lag behind it?

d) What is the average power delivered by the battery anddissipated by each component? e) What is the instantaneous currentin the circuit, I, Vs, VR, VL, VC at t = 3 seconds?

e) What is the instantaneous current in the circuit, I, Vs, VR,VL, VC at t = 3 seconds?

h) Same questions but at the resonance frequency.

Answers according to my professor shouldbe:

c) φ = -.938 rads, The current leads the source voltage by .938rads or the source voltage lags behind the current by .938rads.

d) PbatteryAvg = PresistorAvg = 23.60 watts, PinductorAvg =PcapacitorAvg = 0 watts

e) I(3) = +.0626 amps, Vsource = -128.65 volts, VR = +15.04volts, VC = -288.85 volts, VL = +145.15, Vtot = -128.65 volts[Note: Vsource = Vtot = VL + VC + VR] For instantaneous voltages,they simply add up like a regular addition at any time t!

h) φ = 0 rads, The current is in phase with the sourcevoltage.

PbatteryAvg = PresistorAvg = 67.42 watts,

PinductorAvg = PcapacitorAvg = 0 watts

I(3) = -.478 amps, Vsource = -114.74 volts, VR = -114.74 volts,VC = -269.51 volts, VL = +269.51 volts, Vtot = -114.74 volts

Answer & Explanation Solved by verified expert
4.5 Ratings (796 Votes)
Given Vs 180sin760t L 435 mH C 2 F R 240 The inductive reactance is XL 0435 x 760 3306 The capacitive reactance is XC 106 2x760 65789 The phase angle is The circuit is capacitive as XC is greater than XL Then phase angle is 0938 rad If XC is greaterthan XL then current leads the source voltaged The impedance in the circuit is Z 40586 Vrms V0    See Answer
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