A uniform electric field of magnitude E=270V/m is directed in the positive x direction. A proton moves...

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Physics

A uniform electric field ofmagnitude E=270V/m is directed in the positive x direction. Aproton moves from the origin to the point (x, y)=(20.0cm,50.0cm).
a) Through what potential difference does the charge move?
b) What is the change in the potential energy of the chargefield system?
c) An electron is released at rest at the origin and it moves inthe +x direction. What would be its speed, V_f, after theelectron is released from rest and travels distrance d in theuniform E field? Please derive the express of v_f as afunction of the given quantities: E, d, e (the elementary charge)and m (the mass of the electron).

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Solution Part a A uniform electric field Ex 270Vm is in the positive X direction A proton moves from the origin 00cm 00cm to a point p 200cm 500cm The net displacement in positive X direction is x 20 cm 02 m The electric potential difference between the See Answer

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