mass of the truck m = 1.72*103 kg
radius of the wheel r = 33 cm = 0.33 m
moment of inertia I = 0.800 kg.m2
Truck has 4 wheel.
a)
speed of the truck v = 25 m/s
translational kinetic energy (K.E)t = (1/2) mv2
                                                Â
= (1/2)(1.72*103)(25)2
= 537.5 *10^3 J for 1 wheel
Total translational kinetic energy =
(537.5*103 *4 ) J
= 2150 *10^3 J
b)
speed of the car v = 25 m/s
rotational energy is
         (K.E)r =
(1/2) Iω2    [since ω = v/r]
                    =
(1/2)(I)(v/r)2
                  Â
= (1/2)(0.800)(25/0.33)2
= 2295.68 J for 1 wheel
Total rotational energy of truck =
(2295.68*4)J
= 9182.7 J
