A triangle ABC has sides AB=50 and AC=10. D is mid-point of AB and E is...

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A triangle ABC has sides AB=50 and AC=10. D is mid-point of ABand E is mid-point of AC. Angle bisector AG from vertex A meetsside BC at G and divides it in 5:1 ratio. So BG=5 times GC. AG cutsED at F. Find the ratio of the areas of the trapeziods FDBG toFGCE.

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Ans 51 Refer the solutionbelowConsider lAB50 l AC 10 1BG GC 5 1 givenAssume BG 5x 2GC x 3Now Pt D is    See Answer
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