A transverse harmonic wave travels on a rope according to the following expression: y(x,t) = 0.17sin(2.8x...

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Physics

A transverse harmonic wave travels on a rope according to thefollowing expression: y(x,t) = 0.17sin(2.8x + 17.3t) The massdensity of the rope is μ = 0.107 kg/m. x and y are measured inmeters and t in seconds.

1)

What is the tension in the rope?

2)

At x = 3.5 m and t = 0.4 s, what is the velocity of the rope?(watch your sign)

3)

At x = 3.5 m and t = 0.4 s, what is the acceleration of therope? (watch your sign)

4)

What is the average speed of the rope during one completeoscillation of the rope?

5)

In what direction is the wave traveling?

6)

On the same rope, how would increasing the wavelength of thewave change the period of oscillation?

Answer & Explanation Solved by verified expert
4.1 Ratings (536 Votes)
Since you didnt list question 1 2 I will solve in a minute 3 Looking at the equations we see k2piwavelength Since k is given in the problem you can solve easily for wavelength Now that you know wavelength you can use the equation omegakfrequencywavelength Omega is given in the problem already so    See Answer
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