A thin film having an index of refraction of 1.50 is surrounded by air. It is...

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Physics

A thin film having an index of refraction of 1.50 is surroundedby air. It is illuminated normally by white light. Analysis of thereflected light shows that the wavelengths 360, 450, and 600 nm arethe only missing wavelengths in the visible portion of thespectrum. That is, for those wavelengths, there is destructiveinterference.
(a) What is the thickness of the film?
nm

(b) What wavelengths in the visible portion of the spectrum arebrightest in the reflected interference pattern? (Enter youranswers from smallest to largest.)
? (nm)

(c) If this film were resting on glass that has an index ofrefraction of 1.60, what wavelengths in the visible spectrum wouldbe missing from the reflected light? (Enter your answers fromsmallest to largest.)
....... nm
....... nm
....... nm

Answer & Explanation Solved by verified expert

4.5 Ratings (989 Votes)

Part A For thin film interference of this type the formula that applies is 2nt mwavelength 215t m450 X 109 for the first wavelength then 215t m 1360 X 109 for the second wavelength Lets start from there From the first equation 3t 450 X 109m m 3t450 X 109 Sub into the second 3t m1360 X 109 3t 3t450X 109 1360 X 109 3t 24t 360 X 109 6t 360 X 109 t 6 X See Answer

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