A. The activation energy of a certain reaction is 42.0 kJ/mol . At 29 ∘C ,...

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Chemistry

A. The activation energy of acertain reaction is 42.0 kJ/mol . At 29 ∘C , the rate constant is0.0190s−1. At what temperature in degrees Celsius would thisreaction go twice as fast?

B. Given that the initialrate constant is 0.0190s−1 at an initial temperature of29  ∘C , what would the rate constant be at a temperatureof 120.  ∘C for the same reaction described in PartA?

Please give the correct units too. Thank you!

Answer & Explanation Solved by verified expert
3.9 Ratings (449 Votes)
ExplanationWe can use the Arrhenius equationk A e EaRTherek rate constantA frequency factor and is constantR the gas constant 831 J KmolEa energy    See Answer
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