A stone is thrown with an initial velocity of 31 ft s from the edge...

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Calculus

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A stone is thrown with an initial velocity of 31 ft s from the edge of a bridge that is 44 ft above the ground The height of this stone above the ground t seconds after it is thrown is f t 1612 31t 44 If a second stone is thrown from the ground then its height above the ground after t seconds is given by g t 16t vot where vo is the initial velocity of the second stone Determine the value of v such that the two stones reach the same high point When an object that is thrown upwards reaches its highest point just before it starts to fall back to the ground its bridge use the equation The initial velocity of the second stone would need to be vo Do not round until the final answer Then round to one decimal place will be zero Therefore to find the maximum height of the object thrown from the

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