A spring with a 6-kg mass and a damping constant 5 can be stretched 1.5 meters...

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Advance Math

A spring with a 6-kg mass and a damping constant 5 can bestretched 1.5 meters beyond its natural length and held at restthere by a force of 7.5 newtons. Suppose the spring is stretched 3meters below spring-mass equilibrium and then released with zerovelocity.

Find the position of the mass after t seconds.

y(t)=?

Please show all the work.

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3.7 Ratings (447 Votes)
mass is kga force of 75 N stretches a spring 15 mso x15from the Hookes law    See Answer
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