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A speeding motorist zooms through a 50 km/h zone at 75 km/h (21 m/s) without noticing...

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Physics

A speeding motorist zooms through a 50 km/h zone at 75 km/h (21m/s) without noticing a stationary police car. The police officerimmediatley heads after the speeder, accelerating at 2.5m/s^2. Whenthe officer catches up to the speeder, how far down the raod arethey, and how fast is the police car going?


I know you use the equations x= x_0+ v_0t+ .5at^2 and v= V_0 +at... But I want to know why we use these equations and also howdoes my book derive that when you set the 1st equation for thepolice officer and the speeding motorcycle equal it comes out tobe


x_s= 2v_s0^2/a_p


THank you

Answer & Explanation Solved by verified expert
4.2 Ratings (543 Votes)
75 kmhr 10001 mkm 160 hrmin 160 minsec 750003600 ms 75036 37518 1256 ms Pt 05 a t2 v0 t p0 Well let p0 0 where the patrol car is sitting Well also make the time when the    See Answer
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