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A solution was prepared by dissolving 0.0258 mol disodium phosphate in 500.0mL of deionized water. Phosphoric...

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Chemistry

A solution was prepared by dissolving 0.0258 mol disodiumphosphate in 500.0mL of deionized water. Phosphoric acid has thefollowing pKa values: pKa1 = 2.148 , pKa2 = 7.198 , pKa3 =12.375.

a) What was the pH of the resulting solution?

b) What was the concentration of H2PO4- in the solution?

Answer & Explanation Solved by verified expert
3.7 Ratings (466 Votes)
Solution a The following equilibrium will exists H3PO4 H H2PO4 H2PO4 H HPO42 HPO42 H PO43 Disodium phosphate will dissociate in the deionized water as    See Answer
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