A solution was made by adding water to 0.250 g of H2Z until the volume totaled...

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Chemistry

A solution was made by adding water to 0.250 g of H2Z until thevolume totaled 25.00 mL. Subsequent titration required 40.50 mL of0.100 M sodium hydroxide. Calculate the molar mass of H2Z (ing/mol).

given: H2Z(aq) + 2 NaOH(aq) → Na 2Z(aq) + 2 H2O(ℓ)

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3.9 Ratings (820 Votes)

Number of moles of NaOH , n = Molarity x volume in L

                                            = 0.100 M x (40.50 /1000) L

                                            = 4.05x10-3 mol

H2Z(aq) + 2 NaOH(aq) → Na 2Z(aq) + 2 H2O(ℓ)

From the balanced equation ,

2 moles of NaOH reacts with 1 mole of H2Z

4.05x10-3 mol of NaOH reacts with (4.05x10-3 )/2 = 2.025 x10-3 mole of H2Z

Given mass of H2Z is 0.250 g

We know that Number of moles , n = mass / molar mass

               Molar mass = mass / number of moles

                                   = 0.250 g / (2.025 x10-3 mol)

                                                   = 123.46 g/mol

Therefore the molarmass of H2Z is 123.46 g/mol


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