b)added Br-
concentration=0.560M*1ml/101.4ml=5.52*10-3M
[Ag+]=0.28M*50.2ml/101.4ml=0.139M
[Ti+]=0.28M*50.2ml/101.4ml=0.139M
AgBr ksp=[Ag+][Br-]
TiBr ksp=[Ti+][Br-]
necessary minimum br-
concentration=3.6-6/0.139=2.59*10-5
therefor [Ag+] in
solution=5*10-13/2.59*10-5=1.93*10-8
E=E0+(RT/NF)ln[Ag+]
E=E0+0.0059log[Ag+]
=0.175+0.0059 log1.93*10-8=0.129v
c)added Br-
concentration=0.560M*16.1ml/116.5ml=77.4*10-3M
[Ag+]=0.28M*50.2ml/116.5ml=0.121M
[Ti+]=0.28M*50.2ml/116.5ml=0.121M
AgBr ksp=[Ag+][Br-]
TiBr ksp=[Ti+][Br-]
necessary minimum br-
concentration=3.6*10-6/0.121=2.975*10-5
therefor [Ag+] in
solution=5*10-13/2.975*10-5=1.68*10-8
E=E0+(RT/NF)ln[Ag+]
E=E0+0.0059log[Ag+]
=0.175+0.0059 log1.68*10-8=0.129v
d)added Br- concentration=0.560M*24.1ml/124.5ml=0.108M
[Ag+]=0.28M*50.2ml/124.5ml=0.113M
[Ti+]=0.28M*50.2ml/124.5ml=0.113M
AgBr ksp=[Ag+][Br-]
TiBr ksp=[Ti+][Br-]
necessary minimum br-
concentration=3.6*10-6/0.113=3.18*10-5
therefor [Ag+] in
solution=5*10-13/3.18*10-5=1.57*10-8
E=E0+(RT/NF)ln[Ag+]
E=E0+0.0059log[Ag+]
=0.175+0.0059 log1.57*10-8=0.129v
