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A solution prepared by mixing 22.4 mL of 0.380 M NaCl and 22.4 mL of 0.380...

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Chemistry

A solution prepared by mixing 22.4 mL of 0.380 M NaCl and 22.4mL of 0.380 M KI was titrated with 0.190 M AgNO3 in a cellcontaining a silver indicator electrode and a saturated calomelreference electrode.

(a) What is [Ag ] when 21.2 mL of 0.190 M AgNO3 have been added?Express your answer as x, where [Ag ] is a quotient having the formKsp,AgI/x. (b) What is [Ag ] when 67.0 mL of 0.190 M AgNO3 havebeen added? Express your answer as y, where [Ag ] is a quotienthaving the form Ksp,AgCl/y. (c) Which of the following expressionsshows how cell voltage depends on [Ag ]? (d) The difference between voltages measuredwhen 67.0 mL and 21.2 mL of AgNO3 have been added is 0.3899 V.Using this voltage difference and your answers to questions (a),(b), and (c), calculate the numerical value of the quotientKsp,AgCl/Ksp,AgI.

Answer & Explanation Solved by verified expert
3.7 Ratings (507 Votes)
Moles of Cl in the solution224 ml103    See Answer
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