(Tb - T0b) = kb * molality of solution
(Tb - 100) = 0.52 * (100/180*1000/1000)
Boiling point of the solution Tb = 100.29
P/P0 = mole fraction of Solvent
P = vapour pressure of solution and P0 = vapour pressure
of pure water
P/1 atm = (1000/(100+1000))
P = 0.9091 atm
Osmotic pressure of the solution = C * S *
T
C = concentration of solution ( C = mass/molar mass *
1000/ volume of the solution)
S = solution constant, T = absolute teperature
                              Â
                               Â
= (100/180*1000/1050) * 0.083 * 373
                               Â
= 16.38 atm
