A solution of glucose (C6H12O6) is prepared by dissolving 100.0 g of glucose in 1000. g...

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A solution of glucose (C₆H₁₂O₆)is prepared by dissolving 100.0 g of glucose in 1000. g of water.The density of the resultant solution is 1.050 g/mL. Kb for wateris 0.52 ^oC/m and kf for water is â€“1.86^oC/m.
What is the vapor pressure of the solution at100.0^oC?
What is the boiling point of the solution?
please i really need a clear explanation for this
What is the osmotic pressure of the solution at25^oC?

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3.8 Ratings (491 Votes)

(Tb - T0b) = kb * molality of solution

(Tb - 100) = 0.52 * (100/180*1000/1000)

Boiling point of the solution Tb = 100.29

P/P0 = mole fraction of Solvent

P = vapour pressure of solution and P0 = vapour pressure of pure water

P/1 atm = (1000/(100+1000))

P = 0.9091 atm

Osmotic pressure of the solution = C * S * T

C = concentration of solution ( C = mass/molar mass * 1000/ volume of the solution)

S = solution constant, T = absolute teperature
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = (100/180*1000/1050) * 0.083 * 373

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 16.38 atm

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