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A solution is made by mixing exactly 500.0 mL of 0.167 M NaOH with exactly 500.0...

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Chemistry

A solution is made by mixing exactly 500.0 mL of 0.167 M NaOHwith exactly 500.0 mL of 0.100 M CH3COOH. Calculate theequilibrium concentrations of H3O+,CH3COOH, CH3COO-, OH-,and Na+.

[H3O+] = M

[CH3COOH] =    M

[CH3COO-] =    M

[OH-] = M

[Na+] = M

Answer & Explanation Solved by verified expert
3.8 Ratings (527 Votes)

milli moles of NaOH = 500 x 0.167 = 83.5

milli moles of CH3COOH = 500 x 0.100 = 50

CH3COOH + NaOH   --------------------> CH3COONa + H2O

        50             83.5                                   0 0

0 33.5                                        50                 50

equilibrium concentrations:

[CH3COOH] = 0 M

[CH3COO-] = milli moles of CH3COONa / total volume   

                   = 50 / (500 + 500)

                   = 0.05 M

[OH-] = milli moles of NaOH / total volume   

         = 33.5 / 1000

         = 0.0335 M

[Na+] = milli moles of CH3COONa + milli moles of NaOH / total volume

         = 50 + 33.5 / 1000

         = 0.0835 M

[H3O+] = Kw / [OH-]

             = 1.0 x 10^-14 / 0.0335

             = 2.98 x 10^-13 M

           
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