A solution containing 3.48 mM X (analyte) and 1.67 mM S (internal standard) gave peak areas...

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Chemistry

A solution containing 3.48 mM X (analyte) and 1.67 mM S(internal standard) gave peak areas of 3483 and 10069,respectively, in a chromatographic analysis. Then 1.00 ml of 8.47mM S was added to 5.00 ml of unknown X, and the mixture was dilutedto 10.0 ml. This solution gave peak areas of 5428 and 4431 for Xand S, respectively. Answer the following questions and enter yourresults with numerical values only.
a) Calculate the response factor for the analyte. (keep foursignificant figures)
b) Find the concentration (mM) of X in the 10.0 ml of mixedsolution.
c) Find the concentration (mM) of X in the original unknown.

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3.9 Ratings (765 Votes)

a the response factor for the analyte The response factor F can be expressed as F Area of sample x Conof standard Area of standard x Conof sample 3483 x See Answer

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