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A solution consists of 3.88 g benzene,C6H6 , and 2.45 g toluene ,C6H5CH3. The vapor pressure...

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Chemistry

A solution consists of 3.88 g benzene,C6H6 , and 2.45 g toluene,C6H5CH3. The vapor pressure of pure benzene at 20. °C is 75 mm Hgand that of toluene at 20.0 °C is 22 mm Hg. Assume that Raoult’slawholds for each component of the solution, calculate the molefraction of benzene in the vapor. ( molar mass of benzene= 78.0g/mole and toluene = 92.0 g/mole.)

Answer= 0.87

Answer & Explanation Solved by verified expert
4.2 Ratings (782 Votes)
moles of benzene nB 388 78 00497 moles of toulene nT 245 92 00266 total moles nB nT    See Answer
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