A small object moves along the xx-axis with acceleration
ax(t)ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At tt =
0 the...
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Physics
A small object moves along the xx-axis with accelerationax(t)ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At tt =0 the object is at xx = -14.0 mm and has velocity v0xv0x = 8.70m/sm/s.
What is the xx-coordinate of the object when tt = 10.0 ss?
Express your answer with the appropriate units.
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3.8 Ratings (721 Votes)
Use integration to find the velocity using the equation
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