a sample aqueous solution of iron(iii) sulfate has a mass of 200g, a density of 1.05...

Free

60.1K

Verified Solution

Question

Chemistry

a sample aqueous solution of iron(iii) sulfate has a mass of200g, a density of 1.05 g/cm^3 and 8.35 x10^21 atoms of sulfur.What is the molarity of the solution?

Answer & Explanation Solved by verified expert
4.3 Ratings (840 Votes)

Fe2(SO4)3

1mole of Fe2(SO4)3 contains 3 moles of S

6.023*10^23 molecules of Fe2(SO4)3 contains 3* 6.023*10^23 of S

3 * 6.023*10^23 molecules of S present in 6.023*10^23 molecules of Fe2(SO4)3

8.35*10^21 molecules of S present in 6.023*10^23*8.35*10^21/3*6.023*10^23    = 2.78*10^21 molecules of Fe2(So4)3

6.023*10^23 molecules of Fe2(SO4)3 = 400g

2.78*10^21 molecules of Fe2(SO4)3 = 400*2.78*10^21/6.023*10^23   = 1.85g of Fe2(SO4)3

volume of solution = mass of solution /density

                              = 200g/1.05g/cm^3    = 190.5cm^3

molarity =   W*1000/G.M.Wt* volume of solution in ml

                = 1.85*1000/400*190.5 = 0.0243M >>>>answer


Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:
  • Unlimited Question Access with detailed Answers
  • Zin AI - 3 Million Words
  • 10 Dall-E 3 Images
  • 20 Plot Generations
  • Conversation with Dialogue Memory
  • No Ads, Ever!
  • Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!
Become a Member

Other questions asked by students