A rough analysis of cell contents suggests their cytoplasm contains 5% by weight of solutes: 1%...

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A rough analysis of cell contents suggests their cytoplasmcontains 5% by weight of solutes: 1% is proteins of averagemolecular weight 45,000; 1% is soluble lipids of molecular weight400; 1% is sugars of molecular weight 170; and 2% is salts likeKCl. What is the osmotic pressure inside these cells relative topure water at 37ï‚°C? Assume the density of the cytoplasm isapproximately 1g/cm^3 and has the properties of water.

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4.3 Ratings (751 Votes)

suppose vol of cytoplasm in cell = 1 litre it means 5% of weight of solutes = 5/100*1000 = 50 g

O.P.Â Â Â = molar conc *R*T ....R = 8.314

for proteins ,Â Â molar conc = 10 g/ molecular mass *1000

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â O.P. due to proteins = (10/1000)/45000) * 8.314 * (273+37) = 5.727*10^-4 Pascals

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â \"Â Â Â Â Â Â Â Â Â Â Â soluble lipids = (10 /400*1000 )*8.314 * (273+37) = 0.0644 \"

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â \"Â Â Â Â Â Â Â Â Â Â sugarsÂ Â Â Â = (10/170*1000)*8.314* (273+37)Â Â =0.1516Â Â Â Â Â Â Â Â Â Â Â Â \"

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â \"Â Â Â Â Â Â Â Â Â KClÂ Â Â =Â Â Â (20/74.5*1000) *8.314*(273+37)Â Â = 0.6919Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â \"

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