A researcher wants to determine whether high school students whoattend an SAT preparation course score significantly different onthe SAT than students who do not attend the preparation course. Forthose who do not attend the course, the population mean is 1050 (μ= 1050). The 16 students who attend the preparation course average1150 on the SAT, with a sample standard deviation of 300. On thebasis of these data, can the researcher conclude that thepreparation course has a significant difference on SAT scores? Setalpha equal to .05.

Q1: The appropriate statistical procedure for this example wouldbe a

A. z-test

B. t-test

Q2: The most appropriate null hypothesis (in words) would be

A. There is no statistical difference in SAT scores whencomparing students who took the SAT prep course with the generalpopulation of students who did not take the SAT prep course.

B. There is a statistical difference in SAT scores whencomparing students who took the SAT prep course with the generalpopulation of students who did not take the SAT prep course.

C. The students who took the SAT prep course did not scoresignificantly higher on the SAT when compared to the generalpopulation of students who did not take the SAT prep course.

D. The students who took the SAT prep course did scoresignificantly higher on the SAT when compared to the generalpopulation of students who did not take the SAT prep course.

Q3: The most appropriate null hypothesis (in symbols) wouldbe

A. μSATprep = 1050

B. μSATprep = 1150

C. μSATprep  1050

D. μSATprep  1050

Q4: Based on your evaluation of the null in and your conclusion,as a researcher you would be more concerned with a

A. Type I statistical error

B. Type II statistical error

Calculate the 99% confidence interval. Steps:

Q5: The mean you will use for this calculation is

A. 1050

B. 1150

Q6: What is the new critical value you will use for thiscalculation?

Q7: As you know, two values will be required to complete thefollowing equation:

__________    __________

Q8: Which of the following is a more accurate interpretation ofthe confidence interval you just computed?

A. We are 99% confident that the scores fall in the interval_____ to _____.

B. We are 99% confident that the average score on the SAT by thestudents who took the prep course falls in the interval _____ to_____.

C. We are 99% confident that the example above has correctvalues.

D. We are 99% confident that the difference in SAT scoresbetween the students who took the prep course and the students whodid not falls in the interval _____ to _____.