A report states that adults 18- to 24- years-old send and receive 128 texts every day....

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A report states that adults 18- to 24- years-old send andreceive 128 texts every day. Suppose we take a sample of 25- to 34-year-olds to see if their mean number of daily texts differs fromthe mean for 18- to 24- year-olds.

(a) State the null and alternative hypotheses we should use totest whether the population mean daily number of texts for 25- to34-year-olds differs from the population daily mean number of textsfor 18- to 24-year-olds. (Enter != for ? as needed.)

H0:

Ha:

(b) Suppose a sample of thirty 25- to 34-year-olds showed asample mean of 118.9 texts per day. Assume a population standarddeviation of 33.17 texts per day.

Compute the p-value. (Round your answer to four decimalplaces.)

p-value =

(c) With ? = 0.05 as the level of significance, what isyour conclusion?

(d) Repeat the preceding hypothesis test using the criticalvalue approach.

State the null and alternative hypotheses. (Enter != for ? asneeded.)

H0:

Ha:

(e) Find the value of the test statistic. (Round your answer totwo decimal places.)

State the critical values for the rejection rule. (Use? = 0.05. Round your answer to two decimal places. If thetest is one-tailed, enter NONE for the unused tail.)

test statistic?

test statistic?

(f)

State your conclusion.

Do not reject H0. We cannot conclude thatthe population mean daily texts for 25- to 34-year-olds differssignificantly from the population mean of 128 daily texts for 18-24-year-olds.

Reject H0. We cannot conclude that thepopulation mean daily texts for 25- to 34-year-olds differssignificantly from the population mean of 128 daily texts for 18-24-year-olds.   

Do not reject H0. We can conclude that thepopulation mean daily texts for 25- to 34-year-olds differssignificantly from the population mean of 128 daily texts for 18-24-year-olds.

Reject H0. We can conclude that thepopulation mean daily texts for 25- to 34-year-olds differssignificantly from the population mean of 128 daily texts for 18-24-year-olds.

Answer & Explanation Solved by verified expert
4.0 Ratings (581 Votes)
aH0 128Ha 128bSE 3317 60560Test Statistic is given byZ 1189 12860560 15026Table of Area Under Standard Normal Curve gives area 04332Sop value 05 04332 X 2 01336cSince p value 01335 is greater    See Answer
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