A report classified fatal bicycle accidents according to the month in which the accident occurred, resulting...

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A report classified fatal bicycle accidents according to themonth in which the accident occurred, resulting in the accompanyingtable.

MonthNumber of Accidents
January40
February30
March45
April59
May76
June72
July100
August87
September66
October64
November40
December38

(a) Use the given data to test the null hypothesisH0: p1 =1/12, p2= 1/12, .., p12=1/12, where p1 is the proportion of fatal bicycle accidents thatoccur in January, p2 is the proportion for February, and so on. Usea significance level of 0.01.

Calculate the test statistic. (Round your answer to two decimalplaces.)

?2 =

What is the P-value for the test? (Use a statisticalcomputer package to calculate the P-value. Round youranswer to four decimal places.)

P-value =

What can you conclude?
Reject H0. There is not enough evidence toconclude that fatal bicycle accidents are not equally likely tooccur in each of the months.
Do not reject H0. There is not enough evidenceto conclude that fatal bicycle accidents are not equally likely tooccur in each of the months.
Do not reject H0. There is convincing evidenceto conclude that fatal bicycle accidents are not equally likely tooccur in each of the months.
Reject H0. There is convincing evidence toconclude that fatal bicycle accidents are not equally likely tooccur in each of the months.

(b) The null hypothesis in part (a) specifies that fatalaccidents were equally likely to occur in any of the 12 months. Butnot all months have the same number of days. What null andalternative hypotheses would you test to determine if some monthsare riskier than others if you wanted to take differing monthlengths into account? (Assume this data was collected during a leapyear, with 366 days.) (Enter your probabilities as fractions.)

Identify the null hypothesis by specifying the proportions ofaccidents we expect to occur in each month if the length of themonth is taken into account. (Enter your probabilities asfractions.)

p1= p2=p3=   p4=p5= p6=  p7= p8=p9= p10=p11= p12=

Identify the correct alternative hypothesis.

H0 is true. None of the proportions is notcorrectly specified under H0.
H0 is not true. At least one of the proportionsis not correctly specified under H0.
H0 is true. At least one of the proportions isnot correctly specified under H0.
H0 is not true. None of the proportions iscorrectly specified under H0.

(c) Test the hypotheses proposed in part (b) using a 0.05significance level.

Calculate the test statistic. (Round your answer to two decimalplaces.)

?2 =

What is the P-value for the test? (Use a statisticalcomputer package to calculate the P-value. Round youranswer to four decimal places.)

P-value =

What can you conclude?
Reject H0. There is not enough evidence toconclude that fatal bicycle accidents do not occur in the twelvemonths in proportion to the lengths of the months.
Do not reject H0. There is convincing evidenceto conclude that fatal bicycle accidents do not occur in the twelvemonths in proportion to the lengths of the months.
Do not reject H0. There is not enough evidenceto conclude that fatal bicycle accidents do not occur in the twelvemonths in proportion to the lengths of the months.
Reject H0. There is convincing evidence toconclude that fatal bicycle accidents do not occur in the twelvemonths in proportion to the lengths of the months.

Answer & Explanation Solved by verified expert
3.8 Ratings (413 Votes)

1)applying chi square tesT:

           relative observed Expected residual Chi square
category frequency(p) Oi Ei=total*p R2i=(Oi-Ei)/?Ei R2i=(Oi-Ei)2/Ei
1    1/12 40.000 59.750 -2.56 6.528
2    1/12 30.000 59.750 -3.85 14.813
3    1/12 45.000 59.750 -1.91 3.641
4    1/12 59.000 59.750 -0.10 0.009
5    1/12 76.000 59.750 2.10 4.419
6    1/12 72.000 59.750 1.58 2.512
7    1/12 100.000 59.750 5.21 27.114
8    1/12 87.000 59.750 3.53 12.428
9    1/12 66.000 59.750 0.81 0.654
10    1/12 64.000 59.750 0.55 0.302
11    1/12 40.000 59.750 -2.56 6.528
12    1/12 38.000 59.750 -2.81 7.917
total 1.000 717 717 86.8661

X2 =86.87

p value =0.0000

Reject H0. There is convincing evidence to conclude that fatal bicycle accidents are not equally likely to occur in each of the months.

b)

H0 is not true. At least one of the proportions is not correctly specified under H0.

Applying chi square test:

           relative observed Expected residual Chi square
category frequency(p) Oi Ei=total*p R2i=(Oi-Ei)/?Ei R2i=(Oi-Ei)2/Ei
1 31/366 40.000 60.730 -2.66 7.076
2 29/366 30.000 56.811 -3.56 12.653
3 31/366 45.000 60.730 -2.02 4.074
4    5/61 59.000 58.770 0.03 0.001
5 31/366 76.000 60.730 1.96 3.840
6    5/61 72.000 58.770 1.73 2.978
7 31/366 100.000 60.730 5.04 25.394
8 31/366 87.000 60.730 3.37 11.364
9    5/61 66.000 58.770 0.94 0.889
10 31/366 64.000 60.730 0.42 0.176
11    5/61 40.000 58.770 -2.45 5.995
12 31/366 38.000 60.730 -2.92 8.507
total 1.000 717 717 82.9478

X2 =82.95

p value =0.0000

Reject H0. There is convincing evidence to conclude that fatal bicycle accidents do not occur in the twelve months in proportion to the lengths of the months.


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