A random survey of enrollment at 35 community colleges across the United States yielded the following...

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A random survey of enrollment at 35 community colleges acrossthe United States yielded the following figures: 6,415; 1,549;2,107; 9,348; 21,829; 4,300; 5,943; 5,724; 2,824; 2,043; 5,483;5,199; 5,855; 2,749; 10,010; 6,359; 27,002; 9,416; 7,679; 3,201;17,502; 9,202; 7,380; 18,313; 6,558; 13,714; 17,769; 7,491; 2,769;2,862; 1,262; 7,283; 28,163; 5,082; 11,624. Assume the underlyingpopulation is normal.
Part (a)
Find the following. (Round your answers to the nearest wholenumber.)(i)Â Â Â Â
x =Â Â
s_x=Â Â
n = 35
n âˆ’ 1 = 34
Which distribution should you use for this problem? (Enter youranswer in the form z or t_dfwhere df is the degrees of freedom.)
Part (d)
Construct a 95% confidence interval for the population meanenrollment at community colleges in the United States.(i) State theconfidence interval. (Round your answers to two decimal places.)
( , )

(ii) Sketch the graph. (Round your answers to two decimal places.Enter your Î±/2 to three decimal places.)
CL = 0.95
Î±
2
= 0.025
Î±
2
=0.025Â Â
0.05

(iii) Calculate the error bound. (Round your answer to two decimalplaces.)

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4.2 Ratings (819 Votes)

a x 6415 1549 2107 9348 21829 4300 5943 5724 2824 2043 5483 5199 5855 2749 10010 6359 27002 9416 7679 3201 17502 9202 7380 18313 6558 13714 17769 7491 2769 2862 1262 See Answer

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