A proton with an initial velocity of 3.9 106 m/s enters a parallel-plate capacitor at an...

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Physics

A proton with an initial velocity of 3.9 106 m/s enters aparallel-plate capacitor at an angle of 46Â° through a small hole inthe bottom plate as shown in the figure below. If the plates areseparated by a distance
d = 2.1 cm,
what is the magnitude of the minimum electric field to prevent theproton from hitting the top plate?
___ N/C

Compare your answer with the results obtained if the proton wasreplaced with an electron and choose an answer:

A. The magnitude of the electric field needed for a proton islarger than what is needed for an electron.
B. The magnitude of the electric field needed for a proton issmaller than what is needed for an electron.Â Â Â
C. The magnitude of the electric field needed for a proton isthe same as what is needed for an electron.

Answer & Explanation Solved by verified expert

4.0 Ratings (741 Votes)

Given that initial velocity of proton v0 39 x 106msangle 46 degreeseparation distance between plate d 21 cm 0021 minitial vertical velocity which given as v0y vsin eq1 inserting the values in eq1v0y 39 x 106 ms See Answer

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