A population of squirrels living in a forest with a carrying capacity of 2600.(assume logistics growth with constant k=0.9yr)
(a)find a formula for the squirrels population p(t) assuming an initial population of 650 squirrels.
(b)how long will it take for the squirrels population to double?
(a) p(t)=(pke^(rt))/((k-p)+pe^(rt))
Where p -is the initial population
      k -carrying capacity
      r -growth rate
So , we get
   (650*2600e^(0.9t))/((2600-650)+650e^(0.9t))
=(2600e^(0.9t))/(3+e^(0.9t))
Â
(b) t=1/rln(k-p)/p
   =1/0.9ln(2600-650)/650
   =1/0.9ln3
   =1.2207
(a)=(2600e^(0.9t))/(3+e^(0.9t))
(b)=1.2207
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