A point charge q2 = -1.9 μC is fixed at the origin of a co-ordinate system...

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Physics

A point charge q2 = -1.9 μC is fixed at the origin of aco-ordinate system as shown. Another point charge q1 = 4.5 μC is isinitially located at point P, a distance d1 = 6.6 cm from theorigin along the x-axis

1) What is ΔPE, the change in potenial energy of chargeq1 when it is moved from point P to point R, located adistance d2 = 2.6 cm from the origin along the x-axis asshown?

2) The charge q2 is now replaced by two charges q3 and q4 whicheach have a magnitude of -0.95 μC, half of that of q2. The chargesare located a distance a = 1.6 cm from the origin along the y-axisas shown. What is ΔPE, the change in potential energy now if chargeq1 is moved from point P to point R?

3)What is the potential energy of the system composed of thethree charges q1, q3, and q4, when q1 is at point R? Define thepotential energy to be zero at infinity.

4)The charge q4 is now replaced by charge q5 which has the samemagnitude, but opposite sign from q4 (i.e., q5 = 0.95 μC). What isthe new value for the potential energy of the system?

5)Charges q3 and q5 are now replaced by two charges, q2 and q6,having equal magnitude and sign (-1.9μC). Charge q2 is located atthe origin and charge q6 is located a distance d = d1 + d2 = 9.2cmfrom the origin as shown. What is ΔPE, the change in potentialenergy now if charge q1 is moved from point P to point R?

Answer & Explanation Solved by verified expert
4.2 Ratings (555 Votes)
1ri initial distance between pair of charges 66cm 0066 mrf final distance between pair of charges 26 cm 0026 mUi initial potential    See Answer
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