A point charge of is at the origin, and a second point charge of +6.00nC is...

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Physics

A point charge of is at the origin, and a second
point charge of +6.00nC is on the x axis at x=0.800m Find
the magnitude and direction of the electric field at each
of the following points on the x axis

a)x=20.0cm b)x=1.20m c) -20.0cm

so, since its electric field question using e=k*q/r^2 i cansolve this

so, e= (k*q/r^2) + (k*q/r^2)

so, +6.00nC is on the x axis at x=0.800m....

and -4.00nC is at the origin.. so 0.

a) e= (k*4*10^-9c / 2*10^-2m) + (k*6*10^-9c / .800m ?)  

it say its on the x axis at .800.. right?

Answer & Explanation Solved by verified expert
4.2 Ratings (734 Votes)
E net E1 E2 E3 E K q r2 Where K 1 4 pi eo 900 109 Let the 400 nC charge q1 and the 600 nC q2 Let the distance from q1 to the required    See Answer
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