A plant breeding class scored the seed color and leaf morphology phenotypes of a dry pea...

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Biology

A plant breeding class scored the seed color and leaf morphologyphenotypes of a dry pea population. Seed color was scored based onits genotype (yellow vs. green vs. mixed) and leaf morphology byits phenotype (normal vs. tendrilled). Both traits are controlledby a single gene with complete dominance. The data they collectedfor leaf morphology were: 76 normal: 18 tendrilled and for seedcolor: 18 yellow: 24 green: 52 mixed. Combined phenotypes for thesetraits were 3 yellow, normal; 49 mixed, normal; 24 green, normal;15 yellow, tendrilled; 3 mixed tendrilled; 0 green, tendrilled. Usea Chi square analysis to, first, determine if each gene separatelyfits the expected ratios and, secondly, us e the Chi squareanalysis to determine if the combined phenotypes fit the expectedratio assuming independent assortment. If you reject the hypothesisthat the genes assort independently, explain why.

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As per the statement the two pairs are completely dominant overits allele In a monohybrid cross the ratio of dominant andrecessive traits is 31 It is 3 for the dominant trait and 1 forthe recessive traitThe total offspring are 94 Out of which 76 is normal and 18 istendrilled As per the 31 ratio of the monohybrid cross 71 shouldbe normal 23 should be tendrilledSimilarly if we consider the seed color 18 yellow 24 See Answer

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