A. One beaker contains 10.0 mL of acetic acid/sodium acetate buffer at maximum buffer capacity (equal concentrations...

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Chemistry

A. One beaker contains 10.0 mL ofacetic acid/sodium acetate buffer at maximum buffer capacity (equalconcentrations of acetic acid and sodium acetate), and anothercontains 10.0 mL of pure water. Calculate the hydronium ionconcentration and the pH after the addition of 0.25 mL of
0.10 M HCl to each one. What accountsfor the difference in the hydronium ion concentrations? Explainthis based on equilibrium concepts; in other words, saying thatâ€œone solution is a bufferâ€ is not sufficient.

Ka of acetic acid = 1.8 x 10^-5
Acetic acid/sodium acetate buffer
Acetic acid .1M
Sodium acetate .1M

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3.8 Ratings (362 Votes)

first consider HCl added to pure water we know that moles molarity x volume L so moles of HCl added 01 x 025 x 103 25 x 105 now final volume 10 025 1025 ml now HCl moles volume L HCl 25 x 105 1025 x See Answer

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