A newsgroup is interested in constructing a 90% confidence interval for the proportion of all Americans...

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A newsgroup is interested in constructing a 90% confidenceinterval for the proportion of all Americans who are in favor of anew Green initiative. Of the 588 randomly selected Americanssurveyed, 354 were in favor of the initiative. Round answers to 4decimal places where possible.

a. With 90% confidence the proportion of all Americans who favorthe new Green initiative is between ___?__ and __?___

b. If many groups of 588 randomly selected Americans weresurveyed, then a different confidence interval would be producedfrom each group. About ___?___ percent of these confidenceintervals will contain the true population proportion of Americanswho favor the Green initiative and about ___?___ percent will notcontain the true population proportion.

Answer & Explanation Solved by verified expert
3.9 Ratings (691 Votes)

sample success x = 354
sample size          n= 588
sample proportion p̂ =x/n= 0.6020
std error se= √(p*(1-p)/n) = 0.0202
for 90 % CI value of z= 1.645
margin of error E=z*std error   = 0.0332
lower bound=p̂ -E                       = 0.5688
Upper bound=p̂ +E                     = 0.6352
from above 90% confidence interval for population proportion =(0.5688 ,0.6352)

b)

If many groups of 588 randomly selected Americans were surveyed, then a different confidence interval would be produced from each group. About 90%   of these confidence intervals will contain the true population proportion of Americans who favor the Green initiative and about 10% will not contain the true population proportion


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