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A news report states that the 99% confidence interval for the mean number of daily calories...

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Statistics

A news report states that the 99% confidence interval for themean number of daily calories consumed by participants in a medicalstudy is (2070, 2290). Assume the population distribution for dailycalories consumed is normally distributed and that the confidenceinterval was based on a simple random sample of 22 observations.Calculate the sample mean, the margin of error, and the samplestandard deviation based on the stated confidence interval and thegiven sample size. Use the t distribution in any calculations andround non-integer results to 4 decimal places.

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Solution Given a 99 confidence interval for mean is 2070 2290n 22Upper limit 2290Lower limit 2070We know that the confdience    See Answer
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