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A new operator was recently assigned to a crew of workers who perform a certain job....

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Statistics

A new operator was recently assigned to a crew of workers whoperform a certain job. From the records of the number of units ofwork completed by each worker each day last month, a sample of sizefive was randomly selected for each of the two experienced workersand the new worker. At the α = .05 level of significance,does the evidence provide sufficient reason to reject the claimthat there is no difference in the amount of work done by the threeworkers?

Workers
NewAB
Units of work (replicates)91113
81011
10139
81311
101312

(a) Find the test statistic. (Give your answer correct to twodecimal places.)


(ii) Find the p-value. (Give your answer boundsexactly.)
_____< p < ____

An experiment was designed to compare the lengths of time thatfour different drugs provided pain relief after surgery. Theresults (in hours) follow. Is there enough evidence to reject thenull hypothesis that there is no significant difference in thelength of pain relief provided by the four drugs at α =.05?

Drug
ABCD
4572
5582
36124
459
10

(a) Find the test statistic. (Give your answer correct to twodecimal places.)


(ii) Find the p-value. (Give your answer boundsexactly.)
____< p < ____

Answer & Explanation Solved by verified expert
4.4 Ratings (812 Votes)

Ans a ) using excel>data>data analysis >one way ANOVA

we have

Anova: Single Factor
SUMMARY
Groups Count Sum Average Variance
New 5 45 9 1
A 5 60 12 2
B 5 56 11.2 2.2
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 24.13333 2 12.06667 6.961538 0.009839 3.885294
Within Groups 20.8 12 1.733333
Total 44.93333 14

(a) the test statistic F = 6.96

(ii)the p-value
0.005<p <0.01

Ans 2 )

using excel>data>data analysis >one way ANOVA

we have

Anova: Single Factor
SUMMARY
Groups Count Sum Average Variance
A 4 16 4 0.666667
B 4 21 5.25 0.25
C 5 46 9.2 3.7
D 3 8 2.666667 1.333333
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 101.2208 3 33.74028 20.02721 5.78E-05 3.490295
Within Groups 20.21667 12 1.684722
Total 121.4375 15

(a) the test statistic F = 20.03

(ii)the p-value
0.<p <0.00001
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