A musician in a concert hall is tuning her wind instrument. When she plays a short...

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Physics

A musician in a concert hall is tuning her wind instrument. Whenshe plays a short note she hears the echo of the note return fromthe opposite side of the 50.0 meter long auditorium 0.294 secondslater. Model the instrument as a tube closed at one end, if theinstrument is properly tuned the note of the musician played wouldhave a frequency of 233.082 Hz, but instead has a frequency of226.513 Hz. This note is the first overtone, since the fundamentalfrequency is suppressed on this instrument. 1) What is the speed ofsound in the concert hall on that day? 2) What is the temperatureof the concert hall on that day in Kelvin? 3) What is the length ofthe tubing on the musician's instrument in meters? 4) How much doesthe musician need to change the length of the tubing to be in tuneon that day? Does the tube need to be shortened or lengthened? Findthe change in length of the tube, and make sure to use a negativenumber if the tube needs to be shorter. ( answer in meters.) 5)What is the fundamental frequency of this instrument when correctlytuned? 6) What is the second overtone of the correctly tunedinstrument?  

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3.7 Ratings (292 Votes)
Given datalength of the hall 50 mfrequency of sound 226513 HzThe echo is heard after 0294 s1for the echo the sound has to travel twice    See Answer
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