A musician in a concert hall is tuning her wind instrument. When she plays a short...

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Physics

A musician in a concert hall is tuning her wind instrument. Whenshe plays a short note she hears the echo of the note return fromthe opposite side of the 50.0 meter long auditorium 0.294 secondslater. Model the instrument as a tube closed at one end, if theinstrument is properly tuned the note of the musician played wouldhave a frequency of 233.082 Hz, but instead has a frequency of226.513 Hz. This note is the first overtone, since the fundamentalfrequency is suppressed on this instrument. 1) What is the speed ofsound in the concert hall on that day? 2) What is the temperatureof the concert hall on that day in Kelvin? 3) What is the length ofthe tubing on the musician's instrument in meters? 4) How much doesthe musician need to change the length of the tubing to be in tuneon that day? Does the tube need to be shortened or lengthened? Findthe change in length of the tube, and make sure to use a negativenumber if the tube needs to be shorter. ( answer in meters.) 5)What is the fundamental frequency of this instrument when correctlytuned? 6) What is the second overtone of the correctly tunedinstrument?Â Â

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4.5 Ratings (791 Votes)

1 speed of sound distance time 50 02942 340ms2 Temperature variation speed of sound vT v0 273T273 12where vo 3315 ms is speed of sound at0oC and T See Answer

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